(Sinx-1)(2sin^2x-5sinx+2)=0

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Solution for (Sinx-1)(2sin^2x-5sinx+2)=0 equation: 


Simplifying
(Sinx + -1)(2sin2x + -5sinx + 2) = 0

Reorder the terms:
(-1 + inxS)(2sin2x + -5sinx + 2) = 0

Reorder the terms:
(-1 + inxS)(2 + -5insx + 2in2sx) = 0

Multiply (-1 + inxS) * (2 + -5insx + 2in2sx)
(-1(2 + -5insx + 2in2sx) + inxS(2 + -5insx + 2in2sx)) = 0
((2 * -1 + -5insx * -1 + 2in2sx * -1) + inxS(2 + -5insx + 2in2sx)) = 0
((-2 + 5insx + -2in2sx) + inxS(2 + -5insx + 2in2sx)) = 0
(-2 + 5insx + -2in2sx + (2 * inxS + -5insx * inxS + 2in2sx * inxS)) = 0
(-2 + 5insx + -2in2sx + (2inxS + -5i2n2sx2S + 2i2n3sx2S)) = 0

Reorder the terms:
(-2 + 5insx + 2inxS + -2in2sx + -5i2n2sx2S + 2i2n3sx2S) = 0
(-2 + 5insx + 2inxS + -2in2sx + -5i2n2sx2S + 2i2n3sx2S) = 0

Solving
-2 + 5insx + 2inxS + -2in2sx + -5i2n2sx2S + 2i2n3sx2S = 0

Solving for variable 'i'.

The solution to this equation could not be determined.

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